In the C language, it’s called typecasting: A variable of one type — for an instant — masquerades as another variable type. In Hollywood, however, it’s a curse: The typecast actor can play roles other than the one he’s famous for creating. That sucks.
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\nC language typecasting doesn’t suck. Often it’s necessary to recast a variable as another type to perform an accurate calculation.<\/p>\n
For example, you need to divide two integers. To obtain the correct calculation, you cast each as a float<\/em>. The result can be used immediately or saved in a float<\/em> variable, but it’s a floating-point result and not an int<\/em> value that’s calculated.<\/p>\n For this month’s Exercise, your task is to take an int<\/em> variable If you’re an old hand at C, this Exercise should be easy. If you’re new, then this Exercise is a welcome respite from my recent spate of angry, involved Exercises.<\/p>\n Please attempt this Exercise on your own before you take a peek at my solution<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":" Not every Exercise needs to be a bastard. Continue reading apple<\/code>. Assign it the value 65. Then use three printf()<\/em> statements to display the value of apple<\/code> as an int<\/em>, char<\/em>, and float<\/em>.<\/p>\n