Months have a pattern: All months feature weeks of seven days. The month can start on any day of the week. And months have a varying number of total days, 28, 29, 30, or 31. Given this data, you can display the days and weeks of any month when given only a specific date and the day of the week upon which it falls.
\n
\nFor example, this month is December. It has 31 days, spread across several weeks of 7 days each. The 25th of the month, Christmas, falls on a Tuesday this year. Given this data, you can accurately reconstruct the entire month:<\/p>\n
Sun Mon Tue Wed Thu Fri Sat\r\n 1 \r\n 2 3 4 5 6 7 8 \r\n 9 10 11 12 13 14 15 \r\n 16 17 18 19 20 21 22 \r\n 23 24 25 26 27 28 29 \r\n 30 31<\/code><\/pre>\nYour task for this month’s Exercise is to write a function, month()<\/em>. The function accepts two arguments, day<\/code> and weekday<\/code>: day<\/code> is the day of the month, such as 25 for the 25th, and weekday<\/code> is an integer value 0 through 6 representing Sunday through Saturday.<\/p>\nHere is a skeleton to help get you started, along with a few arguments you need to process to complete the Exercise:<\/p>\n
\r\n#include <stdio.h>\r\n\r\nenum { SUN, MON, TUE, WED, THU, FRI, SAT };\r\n\r\nvoid month(int day, int weekday)\r\n{\r\n\r\n}\r\n\r\nint main()\r\n{\r\n month(15,WED);\r\n month(9,MON);\r\n month(23,SUN);\r\n\r\n return(0);\r\n}<\/pre>\nThe main()<\/em> function contains three statements that the month()<\/em> function must process and output in the calendar-like format shown earlier. For simplicity’s sake, assume that each month has only 30 days. <\/p>\nPlease try this Exercise on your own before you check out my solution<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"Given a day of the week and date of the month, reconstruct the entire month and output it one week. Continue reading