Most functions are nice to strings. They manipulate the characters in a useful or clever way, returning an important value or an updated version of the text. But not every string function needs to be so kind, such as the one you write for this Exercise. The scramble()<\/em> function effectively rearranged all the letters in Onomatopoeia<\/em> into epaOiaaonmto<\/em>. This result could be useful to someone somewhere, but you don’t need to care as you attempt to code the scramble()<\/em> function on your own.<\/p>\n To be kind to you, here is the skeleton you can use to start your coding efforts:<\/p>\n The scramble()<\/em> function accepts the string’s address and its length. Your task is to code the function’s guts, somehow magically rearranging the characters in a random manner. Remember: The function doesn’t return a string; the passed string is modified through pointers. And don’t forget to include the proper header files!<\/p>\n Please try this Exercise on your own before you check out my solution<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":" nSetrrm bil acgaS Continue reading
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\nIt’s called the scramble()<\/em> function. It consumes a string and rearranges the characters in random order. Here’s a sample run:<\/p>\nOriginal: Onomatapoeia
\nScrambled: epaOiaaonmto<\/code><\/p>\n\r\nvoid scramble(char *p,int len)\r\n{\r\n}\r\n\r\nint main()\r\n{\r\n char word[] = \"Onomatapoeia\";\r\n\r\n \/* seed the randomizer *\/<\/span>\r\n srand( (unsigned)time(NULL) );\r\n\r\n \/* scramble the string *\/<\/span>\r\n printf(\"Original: %s\\n\",word);\r\n scramble(word,strlen(word));\r\n printf(\"Scrambled: %s\\n\",word);\r\n\r\n return(0);\r\n}<\/pre>\n