You have a number of options for merging values between two arrays. I suppose the solution you devise depends on how you interpret the word “merge.”
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\nFor example, you could just stick one array onto the end of another:<\/p>\n
You could create a single array and eliminate any overlap between the two, snipping out the duplicate values:<\/p>\n Above, the values 22 and 16 appear only once in the result.<\/p>\n You can also sort the arrays to present the concatenated result sequentially. But for this month’s Exercise, I’d like you to zipper the arrays together. This color-coded sample output saving me many words of text:<\/p>\n I call it a “zipper” because the values from each original array alternate in the result, as shown above.<\/p>\n Your task for this month’s challenge is to write a merge()<\/em> function that swallows two arrays of equal size. It returns a new array that contains values from the two original arrays, but zippered together. (You don’t have to code color output.)<\/p>\n Here is a skeleton to help get you started:<\/p>\n Your merge()<\/em> function sits where the comment is at Line 7 in the code. After the two original arrays Please try this Exercise on your own before you peek at my solution<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":" Don’t just stick one array onto the other, zipper them together! Continue reading Array 'a': 22 41 92 67 16
\nArray 'b': 34 16 57 46 22
\n'a' + 'b': 22 41 92 67 16 34 16 57 46 22<\/code><\/p>\nArray 'a': 22 41 92 67 16
\nArray 'b': 34 16 57 46 22
\n'a' + 'b': 22 41 92 67 16 34 57 46<\/code><\/p>\nArray 'a': 22 41 92 67 16<\/span>
\nArray 'b': 34 16 57 46 22<\/span>
\n'a'<\/span> + 'b'<\/span>: 22<\/span> 34<\/span> 41<\/span> 16<\/span> 92<\/span> 57<\/span> 67<\/span> 46<\/span> 16<\/span> 22<\/span><\/code><\/p>\n2023_03_01-Lesson.c<\/a><\/h3>\n
\r\n#include <stdio.h>\r\n#include <stdlib.h>\r\n#include <time.h>\r\n\r\n#define SIZE 5\r\n\r\n\/* merge function goes here *\/<\/span>\r\n\r\nint main()\r\n{\r\n int x,a[SIZE],b[SIZE],*c;\r\n\r\n \/* seed the randomizer *\/<\/span>\r\n srand( (unsigned)time(NULL) );\r\n\r\n \/* populate the arrays, values 0 through 99 *\/<\/span>\r\n for( x=0; x<SIZE; x++ )\r\n {\r\n a[x] = rand()%100;\r\n b[x] = rand()%100;\r\n }\r\n\r\n \/* output the arrays *\/<\/span>\r\n printf(\"Array 'a': \");\r\n for( x=0; x<SIZE; x++ )\r\n printf(\" %2d\",a[x]);\r\n putchar('\\n');\r\n printf(\"Array 'b': \");\r\n for( x=0; x<SIZE; x++ )\r\n printf(\" %2d\",b[x]);\r\n putchar('\\n');\r\n\r\n \/* call the merge() function *\/<\/span>\r\n \/* output the merged arrays *\/<\/span>\r\n\r\n return(0);\r\n}\r\n<\/pre>\na[]<\/code> and b[]<\/code> are stuffed with random values and output, the merge()<\/em> function is called. Then, in the main()<\/em> function, output the merged arrays, as shown earlier.<\/p>\n