When I was working on last month’s Exercise<\/a>, I scoured the C library for a function that returned the number of specific characters found in a string. The closest I could find was strchr()<\/em>, which returns the location of a given character in a string. You can set this function in a loop to find subsequent characters, but what I needed was a tally, a total count of all matching characters in the string. Don’t use your eyeballs to count! No, your task for this month’s Exercise is to code a function charcount()<\/em>. It accepts two arguments, a string to scan and the character to count. The function returns the number of characters found.<\/p>\n You can use this sample code to get you started, which is missing the charcount()<\/em> function details, of course:<\/p>\n Here is a sample run from my solution:<\/p>\n Your task is to complete the charcount()<\/em> function. Please try this Exercise on your own before you check out my solution<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":" How many characters c<\/em> are found in a string? Continue reading
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\nFor example, given the string \"She sells seashells by the seashore\"<\/code>, how many letters s<\/code> (lowercase only) are found in the string?<\/p>\n2023_09_01-Lesson.c<\/a><\/h3>\n
\r\n#include <stdio.h>\r\n\r\nint charcount(char *s,char c)\r\n{\r\n}\r\n\r\nint main()\r\n{\r\n const int size = 64;\r\n char buffer[size];\r\n char c,t;\r\n\r\n printf(\"Enter a string: \");\r\n fgets(buffer,size,stdin);\r\n printf(\"Enter a character to find: \");\r\n scanf(\"%c\",&c);\r\n\r\n t = charcount(buffer,c);\r\n printf(\"There are %d letters '%c' in: %s\",\r\n t,\r\n c,\r\n buffer\r\n );\r\n\r\n return(0);\r\n}<\/pre>\nEnter a string: She sells seashells by the seashore
\nEnter a character to find: s
\nThere are 7 letters 's' in: She sells seashells by the seashore<\/code><\/p>\n