Solution for Exercise 5-1
ex0501
#include <stdio.h> int main() { printf("The value %d is an integer.\n",986); printf("The value %f is a float.\n",98.6); return(0); }
Notes
* Two items are used in both printf() functions that don't display as shown in the source code: conversion characters and escape characters.
* Conversion characters are prefixed by a %
(percent sign), escape characters are prefixed by a \
(backslash).
* Conversion characters can also be called placeholders.
* To display a % in a string, you must specify two % characters, %%
. Even the pros forget to do that from time to time. So to print 50%
you use this statement:
Or:
* Likewise, to display a \ in a string, you must specify two of them, \\
.
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