Solution for Exercise 5-9

ex0509

#include <stdio.h>

int main()
{
    printf("The total is %d\n",16.0+17);
    return(0);
}

* The compiler reads value 16.0 as a float because of the .0 part. The value 17 is still assumed to be an int.

* The result I saw on one of my test computers was:

The total is 1606416648

* The value isn't random. Instead, it's the printf() function trying to interpret what's become a floating point value as an int thanks to %d.