Solution for Exercise 6-7

ex0607

#include <stdio.h>

int main()
{
    unsigned int ono;

    ono = -10;
    printf("The value of ono is %u.\n",ono);
    return(0);
}

Notes

* The - unary operator is used to assign the value negative ten to the variable ono. I recognize that you probably just accept -10 as a value, but it's really the value 10 with the - (negative) unary operator prefixed.

* If you change the %u placeholder to %d in Line 8, the result displayed is -10. As with floating point numbers and precision, the value -10 is stored only one way inside the computer. It can be displayed as an unsigned value, 4294967286, or it can be displayed as a signed value, -10. The display depends on the conversion character used.

* Remember, even though the conversion character controls the display, some functions require or return unsigned int values. When you don't specify an unsigned int value, the compiler complains.

Exercise ex0608 →