Solution for Exercise 9-4

ex0904

#include <stdio.h>

int main()
{
    int count;

    for(count=11; count<=19; count=count+1)
    {
        printf("%d\t",count);
    }
    putchar('\n');
    return(0);
}

Notes

* The first task was to have the loop display values 11 through 19. The value of count is initialized to 11 in Line 7.

* The ending value of 19 is also specified at Line 7, in the for statement. The<= operator is used, so the value 19 can be specified directly. Otherwise, if < was used, the comparision would have to be count<20.

* The "repeat each" part of the loop remains the same so that values from 11 through 19 are displayed one after the other.

* In Line 9, the \t escape sequence represents the Tab character, which separates each value displayed.

* Finally, Line 11 adds the putchar() function with the \n newline character. That newline cleans up the output. Of course, you could also use a printf() function to display the new line, as in:

printf("\n");

* On my screen, the output looks like this:

11 12 13 14 15 16 17 18 19

Exercise ex0905 →