Solution for Exercise 9-7

ex0907

#include <stdio.h>

int main()
{
    int backwards;

    for(backwards=25;backwards>=0;backwards=backwards-1)
    {
        printf("%d\n",backwards);
    }
    return(0);
}

Notes

* Line 7 is the one to get correct, regardless of whether you used the variable name backwards or not.

* You could have specified backwards>-1 as the second condition in the for statement. As long as zero is the final value displayed, the loop is correct.

Exercise ex0908 →