Solution for Exercise 11-6

ex1106

#include <stdio.h>

int main()
{
    int a,b;

    b=16;
    printf("Before, a is unassigned and b=%d\n",b);
    a=++b;
    printf("After, a=%d and b=%d\n",a,b);
    return(0);
}

Notes

* Because the ++ (increment operator) appears before variable b at Line 9, its value is incremented first. Then the result is assigned to variable a.

* Here is the program's output:

Before, a is unassigned and b=16 After, a=17 and b=17

* It's important to remember when a value is incremented or decremented lest your code not behave as intended.

Exercise ex1107 →