Solution for Exercise 11-18
ex1118
#include <stdio.h>
#include <stdlib.h>
int main()
{
int r,a,b;
puts("100 Random Numbers");
for(a=0;a<20;a++)
{
for(b=0;b<5;b++)
{
r=rand();
r%=21;
printf("%d\t",r);
}
putchar('\n');
}
return(0);
}
Notes
* The result of the program is to display 100 random numbers in the range of 0 through 20.
* The zero is possible because r%=21 generates a value of zero when the random number coughed up by the rand() function is divisible by 21.
* You could also combine Lines 13 and 14 to read:
* Most of the random number generating routine you'll use incorporate the modulus operator to curb the values, just as shown above.
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