Solution for Exercise 11-18
ex1118
#include <stdio.h> #include <stdlib.h> int main() { int r,a,b; puts("100 Random Numbers"); for(a=0;a<20;a++) { for(b=0;b<5;b++) { r=rand(); r%=21; printf("%d\t",r); } putchar('\n'); } return(0); }
Notes
* The result of the program is to display 100 random numbers in the range of 0 through 20.
* The zero is possible because r%=21
generates a value of zero when the random number coughed up by the rand() function is divisible by 21.
* You could also combine Lines 13 and 14 to read:
* Most of the random number generating routine you'll use incorporate the modulus operator to curb the values, just as shown above.
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