Solution for Exercise 12-24
ex1224
#include <stdio.h> #define SIZE 5 void showarray(int array[]); void arrayinc(int array[]); int main() { int n[] = { 1, 2, 3, 5, 7 }; puts("Original array:"); showarray(n); arrayinc(n); puts("After calling the arrayinc() function:"); showarray(n); return(0); } void showarray(int array[]) { int x; for(x=0;x<SIZE;x++) printf("%d\t",array[x]); putchar('\n'); } void arrayinc(int array[]) { int x; for(x=0;x<SIZE;x++) array[x]++; }
Notes
* The code uses the ++
increment operator at Line 34 to add one to the value of each array element. I could have also used the +=
assignment operator, as in array[x]+=1
, but ++
is more to the point.
* Here is sample output:
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