Solution for Exercise 14-6

ex1406

#include <stdio.h>

int main()
{
    struct scores
    {
        char name[32];
        int score;
    };
    struct scores player[4];
    int x;

    for(x=0;x<4;x++)
    {
        printf("Enter player %d: ",x+1);
        scanf("%s",player[x].name);
        printf("Enter their score: ");
        scanf("%d",&player[x].score);
    }

    puts("Player Info");
    printf("#\tName\tScore\n");
    for(x=0;x<4;x++)
    {
        printf("%d\t%s\t%5d\n",
            x+1,player[x].name,player[x].score);
    }
    return(0);
}

Notes

* The printf() statement at Line 22 may look a bit odd, but it's just the \t escape sequence, which I use to line up output. Those same characters (tabs) appear in the printf() statement at Lines 25 and 26 to line up output.

Exercise ex1407 →