Solution for Exercise 17-10

ex1710

#include <stdio.h>

char *binbin(int n);

int main()
{
    int bshift,x;

    printf("Type a value from 0 to 255: ");
    scanf("%d",&bshift);

    for(x=0;x<8;x++)
    {
        printf("%s\n",binbin(bshift));
        bshift = bshift << 1;
    }

    return(0);
}

char *binbin(int n)
{
    static char bin[9];
    int x;

    for(x=0;x<8;x++)
    {
        bin[x] = n & 0x80 ? '1' : '0';
        n <<= 1;
    }
    bin[x] = '\0';
    return(bin);
}

Notes

* Below you see the output from Exercise 17-10 when I input the value 1:

Type a value from 0 to 255: 1 00000001 00000010 00000100 00001000 00010000 00100000 01000000 10000000

You can see the 1 bit march left across each position in the byte. That's the shift in action.

Exercise ex1711 →