Solution for Exercise 18-6
ex1806
#include <stdio.h>
int main()
{
    char c = 'c';
    int i = 123;
    float f = 98.6;
    double d = 6.022E23;
    printf("Address of 'c' %p\n",&c);
    printf("Address of 'i' %p\n",&i);
    printf("Address of 'f' %p\n",&f);
    printf("Address of 'd' %p\n",&d);
    return(0);
}
Notes
* Yes, this source code is based on Listing 18-1, as well as Exercise 18-1.
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