Solution for Exercise 18-12

ex1812

#include <stdio.h>

int main()
{
    int i = 1814;
    int *pi = &i;

    printf("The value of 'i' is %d.\n",*pi);
    return(0);
}

Notes

* The int variable i is declared at Line 5.

* The int pointer variable pi is declared at Line 6, plus it's immediately initialized to the address of int variable i. This approach is different from using two separate statements because the * is used to declare a pointer variable, but you don't use the * when initializing a pointer variable to an address. Here are the two statements you could otherwise use:

int *pi; pi = &i;

* Line 8 displays the value assigned to variable i (at Line 5) by referring to the pointer *pi.

Exercise ex1813 →