Solution for Exercise 19-8

ex1908

#include <stdio.h>

int main()
{
    char alphabet[27];
    int x;
    char *pa;

    pa = alphabet;      /* initialize pointer */

/* Fill array */
    for(x=0;x<26;x++)
    {
        *pa++=x+'A';
    }

    pa = alphabet;

/* Display array */
    for(x=0;x<26;x++)
    {
        putchar(*pa);
        pa++;
    }
    putchar('\n');

    return(0);
}

Notes

* In the *pa++ operation, the ++ actually binds more tightly than the *. Both the ++ and * operators have the same level in the Sacred Order of Precedence, but the operators are read right-to-left. Even so, because the ++ is postfixed, the address at pa is used first (before it's incremented). So * reads the value at that address, then the address is incremented. If it worked the other way, then the display part of the code would show only letters A through Y.

Exercise ex1909 →