Solution for Exercise 21-10

ex2110

#include <stdio.h>
#include <time.h>

int main()
{
    time_t tictoc;
    struct tm *today;
    char *weekday[] = {
        "Sunday",
        "Monday",
        "Tuesday",
        "Wednesday",
        "Thursday",
        "Friday",
        "Saturday"
    };

    time(&tictoc);
    today = localtime(&tictoc);
    printf("Today is %s, %d/%d/%d\n",
        *(weekday+today->tm_wday),
        today->tm_mon+1,
        today->tm_mday,
        today->tm_year+1900);
    return(0);
}

Notes

* The array of weekday string pointers is defined at Line 8. The order of the days is important! The tm_wday element starts numbering days with 0 for Sunday.

* The day of the week is displayed by using pointer notation at Line 21. It's the *(p+x) variation, which is similar to array[x]. In fact, here is the equivalent way of expressing that line by using an array:

weekday[today->tm_wday],

* I hope you remembered to modify Lines 22 and 24 so that the month and year are displayed properly.

* Sample output:

Today is Thursday, 4/2/2013

Exercise ex2111 →