Solution for Exercise 25-2

ex2502

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int x;
    int *px;

    px=&x;
    for(x=0;x<10;x++)
        printf("%d\n",*px);
    return 0;
}

Notes

* This code contains no errors. The book's text implies it might, but it doesn't. The purpose is merely to monitor the variables x and px from within the debugger.

Exercise ex2503 →