Solution for Exercise 10-9

ex1009

#include <stdio.h>

float convert(float f);

int main()
{
    float temp_f,temp_c;

    printf("Temperature in Fahrenheit: ");
    scanf("%f",&temp_f);
    temp_c = convert(temp_f);
    printf("%.1fF is %.1fC\n",temp_f,temp_c);
    return(0);
}

float convert(float f)
{
    float t;

    t = (f - 32) / 1.8;
    return(t);
}

Output

Temperature in Fahrenheit: 50
50.0F is 10.0C

Notes

* I used the underscore in temp_f and temp_c to avoid having f and c as variable names. I wanted to use fahrenheit and celsius as the names, but it made the printf() statement too long and it would have wrapped and looked ugly in the book.

* Don't let the %.1f conversion character vex you. It's still the %f conversion character, but with extra arguments between the % and f. Also, the big F afterwards might look confusing, but it's just another character in the string and not part of the conversion character. Editors that color-code text render it nicely.

Exercise ex1010 →