Solution for Exercise 12-21

ex1221

#include <stdio.h>

int main()
{
    char tictactoe[3][3][3];
    int x,y,z;

    /* initialize matrix */
    for(x=0;x<3;x++)
        for(y=0;y<3;y++)
            for(z=0;z<3;z++)
                tictactoe[x][y][z]='.';
    tictactoe[1][1][1] = 'X';

    /* display game board */
    puts("Ready to play 3D Tic-Tac-Toe?");
    for(z=0;z<3;z++)
    {
        printf("Level %d\n",z+1);
        for(x=0;x<3;x++)
        {
            for(y=0;y<3;y++)
                printf("%c ",tictactoe[x][y][z]);
            putchar('\n');
        }
    }
    return(0);
}

Output

Ready to play 3D Tic-Tac-Toe?
Level 1
. . .
. . .
. . .
Level 2
. . .
. X .
. . .
Level 3
. . .
. . .
. . .

Notes

* The z+1 at Line 19 doesn't modify the value of variable z. Its effect is to display values 1 through 3 when the 3D array is output. Otherwise, values 0 through 2 are displayed, which would freak out the humans.

Exercise ex1222 →