Solution for Exercise 12-21
ex1221
#include <stdio.h> int main() { char tictactoe[3][3][3]; int x,y,z; /* initialize matrix */ for(x=0;x<3;x++) for(y=0;y<3;y++) for(z=0;z<3;z++) tictactoe[x][y][z]='.'; tictactoe[1][1][1] = 'X'; /* display game board */ puts("Ready to play 3D Tic-Tac-Toe?"); for(z=0;z<3;z++) { printf("Level %d\n",z+1); for(x=0;x<3;x++) { for(y=0;y<3;y++) printf("%c ",tictactoe[x][y][z]); putchar('\n'); } } return(0); }
Output
Ready to play 3D Tic-Tac-Toe?
Level 1
. . .
. . .
. . .
Level 2
. . .
. X .
. . .
Level 3
. . .
. . .
. . .
Notes
* The z+1
at Line 19 doesn't modify the value of variable z
. Its effect is to display values 1 through 3 when the 3D array is output. Otherwise, values 0 through 2 are displayed, which would freak out the humans.
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