Solution for Exercise 17-1

ex1701

#include <stdio.h>

char *binbin(unsigned char n);

int main()
{
    unsigned input;

    printf("Type a value 0 to 255: ");
    scanf("%u",&input);
    printf("%u is binary %s\n",
            input,binbin((unsigned char)input));
    return(0);
}

char *binbin(unsigned char n)
{
    static char bin[9];
    int x;

    for(x=0;x<8;x++)
    {
        bin[x] = n & 0x80 ? '1' : '0';
        n <<= 1;
    }
    bin[x] = '\0';
    return(bin);
}

Output

Type a value 0 to 255: 43
43 is binary 00101011

Notes

* Yeah, I got it correct in the book, Figure 17-1.

* The %u conversion character represents unsigned integer values.

Exercise ex1702 →