Solution for Exercise 17-5

ex1705

#include <stdio.h>

char *binbin(unsigned char n);

int main()
{
    const int set = 223;
    unsigned int bor,result;

    printf("Type a value from 0 to 255: ");
    scanf("%u",&bor);
    result = bor & set;

    printf("\t%s\t%d\n",
            binbin((unsigned char)bor),bor);
    printf("&\t%s\t%d\n",
            binbin((unsigned char)set),set);
    printf("=\t%s\t%d\n",
            binbin((unsigned char)result),result);
    return(0);
}

char *binbin(unsigned char n)
{
    static char bin[9];
    int x;

    for(x=0;x<8;x++)
    {
        bin[x] = n & 0x80 ? '1' : '0';
        n <<= 1;
    }
    bin[x] = '\0';
    return(bin);
}

Output

Type a value from 0 to 255: 170
        10101010        170
&       11011111        223
=       10001010        138

Exercise ex1706 →