Solution for Exercise 18-8

#include <stdio.h>

int main()
{
    int array[5] = { 100, 200, 300, 400, 500 };
    int x;

    for(x=0;x<5;x++)
        printf("%d at %p\n",array[x],&array[x]);
    return(0);
}

Output

100 at 0x7ffeeb788a00
200 at 0x7ffeeb788a04
300 at 0x7ffeeb788a08
400 at 0x7ffeeb788a0c
500 at 0x7ffeeb788a10

Exercise ex1809 →