Solution for Exercise 19-22

ex1922

#include <stdio.h>

void discount(float *a);

int main()
{
    float price = 42.99;

    printf("The item costs $%.2f\n",price);
    discount(&price);
    printf("With the discount, that's $%.2f\n",price);
    return(0);
}

void discount(float *a)
{
    *a *= 0.90;
}

Output

The item costs $42.99
With the discount, that's $38.69

Notes

* Line 17 may look odd because the * character is used as both the pointer and multiplication operators. Such things happen often in C.

Exercise ex1923 →