Solution for Exercise 03_02-scanf2.c

03_02-scanf2.c

#include <stdio.h>

int main()
{
	int count,x,*c;

	c = &count;
	printf("Enter repeat count: ");
	/* no ampserand for a pointer */
	scanf("%d",c);

	for( x=0; x<count; x++ )
		puts("Oh boy!");

	return 0;
}

Output

Enter repeat count: 5
Oh boy!
Oh boy!
Oh boy!
Oh boy!
Oh boy!

Notes

* Pointer variable c is declared in the same statement as variables count and x. All three are integer variables.

* Pointer c is initialized, assigned to the address of variable count: c = &count;

* In the scanf() statement, pointer variable c is used as the second argument. No & (address-of) operator is required in that c is an address (a pointer): scanf("%d",c);

* The result is that the repeat value is assigned to variable count and used in the for loop with the value that the user input.

Exercise 03_04-added.c →