Solution for Exercise 6-6

ex0606

#include <stdio.h>

#define GLORKUS 16

int main()
{
    int blorf;

    blorf = 22;

    printf("The value of blorf is %d.\n",blorf);
    printf("The value of blorf plus 16 is %d.\n",blorf+GLORKUS);
    printf("The value of blorf times itself is %d.\n",blorf*blorf);
    return(0);
}

Notes

* The above solution is okay, but the following solution is better:

#include <stdio.h>

#define GLORKUS 16

int main()
{
    int blorf;

    blorf = 22;

    printf("The value of blorf is %d.\n",blorf);
    printf("The value of blorf plus %d is %d.\n",GLORKUS,blorf+GLORKUS);
    printf("The value of blorf times itself is %d.\n",blorf*blorf);
    return(0);
}

* In Line 12, the value of GLORKUS is shown immediately in the printf() funciton by using the %d conversion character. I highly recommend this solution as it allows you to change the constant later without having to search through the code and look for any immediate references to its value.

Exercise ex0607 →